The Mechanical
Engineering Handbook




Energy Stored Inside A Capactitor Calculator












How This Is Calculated



$$ E = \frac{1}{2} CV^2 $$
where:

E   =   Energy Stored   (J)

C   =   Capacitance   (C)

V   =   Voltage   (V)


Assumptions



  • The capacitor is ideal (no energy losses to resistive, dielectric or leakage effects).
  • The electric field between plates is uniform.
  • Fringing effects are ignored.
  • The capacitor is in a steady state condition.


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